Factorise: 49 a^{2}+70 a b+25 b^{2} | vedclass

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(B) To factorise the expression $49 a^{2}+70 a b+25 b^{2}$,we observe the terms:$49 a^{2} = (7 a)^{2}$$25 b^{2} = (5 b)^{2}$$70 a b = 2(7 a)(5 b)$Comp

Vedclass · Accepted Answer

$(7a+5b)^{2}$

Vedclass · Answer

(B) To factorise the expression $49 a^{2}+70 a b+25 b^{2}$,we observe the terms:$49 a^{2} = (7 a)^{2}$$25 b^{2} = (5 b)^{2}$$70 a b = 2(7 a)(5 b)$Comparing this with the algebraic identity $(x+y)^{2} = x^{2}+2 x y+y^{2}$,we identify $x = 7 a$ and $y = 5 b$.Substituting these values into the identity,we get:$49 a^{2}+70 a b+25 b^{2} = (7 a+5 b)^{2} = (7 a+5 b)(7 a+5 b)$.

Factorise: $49 a^{2}+70 a b+25 b^{2}$

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